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Math 142 Test1 S22
发布时间:2023-07-28
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Test 2
1 (a) (7 points) For
+
66
= 0 , show that if
=
,then p is constant along (t) .
Explain why z(t) is a straight line.
b) (7 p
ints) suppose instead that
t + ![]()
=
a(t) with
=
, given
( 0 )=0 ,p(o0)
rt-plane.
10 , with u ()= 30 . 1p. solve for
= 100 . sketch the solutions in the
2 · (a) (8 points) prove that if C is constant , then all solutions to
+ cdd
= 0 are of the
form p(r , t) = f(
ct) , where f(
) =p(
0) .
(b) (4 points) suppose u(
) = 60 - 4p, and p(
,0) = 5 +1(2+
) · Find an approxi-
mate solution p(w t) .
(c) (4 points) sketch p(
0) ,p(r , 1) , and p(r , 2) , from your approximation above.
5
2
U(
) = 75 3
2 .
(a) (10 points) solve for p(
,t) in all regions of the (w , t) -plane.
(b) (4 points) sketch the characteristics in all regions of the (w , t) -plane.
(c) (4 points) sketch a graph of p(r , 1) .
(d) (10 points) solve for the path of a car
(t) in this situation, if r() = 0 .
Test 3
(g0)=
1 +2 0<
<3
7
≥ 3
u( )=10
·
(a) (6 points) Find where a shock occurs and the exact line of the shock.
(b) (10 points) solve for p(r , t) in all regions of the (w , t) -plane.
(c) (5 points) sketch the characteristics in the
t-plane.
(d) (3 points) sketch p(
· 1) .
(e) (3 points) sketch p(r , . 5) .
5
suppose ![]()
pt +
6p = 0 , U ()= 50 . 25p, and
1 p(
0)
1 1 2 3 4 5
A Shock will form along a characteristic from
to (
S
ts) in the
(r , t) plane.
(a) (9 points) Find
*
(b) (3 points) Find ts
(c) (3 points) Find
s ·
