MATH 1053 – Quantitative Methods for Business External Assignment 3
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MATH 1053 – Quantitative Methods for Business
External Assignment 3
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c. The most frequent value between 15 and 20 without waiting for tracking. It has two peaks. The graph is skewed to the right, the mean>the median. The observations are not symmetrically distributed. They are concentrated at one end, with a tail. The first quartile is 1.5 x 20 is 21 and it's not greater than the third quartile so it's not an outlier.
The value that occurs most frequently at 15 in the case of waiting for tracking. It has a peak. This plot is also skewed to the right, with mean > median. The observations are not symmetrically distributed. They are concentrated at one end, with a tail. The first quartile is 1.5 x 12 is 18, which is not larger than the third quartile, so it is not an outlier.
d. The measures of dispersion of the first graph WITHOUT wait-tracking, which needs to consider the value of mean, because this graph is skewed of the right, mean is greater than median. so use the formula IQR=Q3-Q1 =34-20=14 minutes.
The measures of dispersion of the second graph WITHOUT wait-tracking, which needs to consider the value of mean, because this graph is skewed of the right, mean is greater than median. so use the formula IQR=Q3-Q1 =18-12=6 minutes.
e. According to figure1.side-by-side boxplots this shows the maximum and minimum values of without wait-tracking and with wait-tracking.This type of graph helps with side-by-side comparisons. It allows comparing the position of the median and the presence of outliers. Also allows comparison of overall shape (symmetric, skewed), minimum and maximum values.
f. The two are different in that the frequency of occurrence of without wait- tracking is not the same as the frequency of occurrence of with wait-tracking. The introduction of the tracking system saves time for patients, avoiding excessive queuing and delays, which can help more patients and treat them accurately. The manager has achieved an average wait time of 15 minutes for patients to see a doctor.
2.
a. The independent variable is Gift Card Sales, the dependent variables is Revenue.
b. According to the scatter plot, this is positive linear, linear tends to increase, y=k x+ b , r has no units,is always equal 1 and -1.
∑( −)( −)
∑( −)( −)
D. I think there are points with any data, because according to the picture, there are some points with too big discrete distance and an upward trend, already sold 12million, why some points are still below the line, so I think there is an undue influence.
E. The slope is the rate of growth between gift card sales and revenue in this scenario and this is meaningful.
F. = 4.4204 + 6.2339
When x equal to 7, = 4.4204 × 7 + 6.2339 = 37.1767.My analysis is accurate because this figure is close to the income, so this is accurate.
2022-05-13